Binomial series

Results: 73



#Item
41COMBINATORIAL IDENTITIES AND INVERSE BINOMIAL COEFFICIENTS TOUFIK MANSOUR Department of Mathematics, University of Haifa, Haifa, Israel 31905

COMBINATORIAL IDENTITIES AND INVERSE BINOMIAL COEFFICIENTS TOUFIK MANSOUR Department of Mathematics, University of Haifa, Haifa, Israel 31905

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Source URL: math.haifa.ac.il

Language: English - Date: 2005-02-09 02:11:29
42Best Practice Recommendation for Forecasting Counts Brajendra C. Sutradhar Department of Mathematics and Statistics, Memorial University of Newfoundland St. John’s, NL, Canada A1C 5S7

Best Practice Recommendation for Forecasting Counts Brajendra C. Sutradhar Department of Mathematics and Statistics, Memorial University of Newfoundland St. John’s, NL, Canada A1C 5S7

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Source URL: forecasters.org

Language: English - Date: 2008-07-30 14:29:40
43The Package HYPQ for handling basic hypergeometric series (q-series) Loading the package: In[1]:= << hyp.q The basic objects. The q-binomial coefficient:

The Package HYPQ for handling basic hypergeometric series (q-series) Loading the package: In[1]:= << hyp.q The basic objects. The q-binomial coefficient:

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Source URL: www.ima.umn.edu

Language: Albanian - Date: 2002-08-28 11:42:52
    44PROBLEM OF THE WEEK Solution of Problem No. 2 (Spring 2014 Series) Problem: It is known that, for any positive integer m, X

    PROBLEM OF THE WEEK Solution of Problem No. 2 (Spring 2014 Series) Problem: It is known that, for any positive integer m, X

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    Source URL: www.math.purdue.edu

    Language: English - Date: 2014-02-11 13:26:55
    45Probability Reference Combinatorics and Sampling A permutation is an ordered selection. The number of permutations of k items picked from a list of n items, without replacement, is P (n; k) := n(n |

    Probability Reference Combinatorics and Sampling A permutation is an ordered selection. The number of permutations of k items picked from a list of n items, without replacement, is P (n; k) := n(n |

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    Source URL: uhaweb.hartford.edu

    Language: English - Date: 2014-02-20 15:32:39
    4615 Higher and Super Calculus of Elliptic Integral 15.1 Double series expansion of Elliptic Integral[removed]Double series expansion of Elliptic Integral of the 1st kind Formula[removed]The following expressions hold for |k

    15 Higher and Super Calculus of Elliptic Integral 15.1 Double series expansion of Elliptic Integral[removed]Double series expansion of Elliptic Integral of the 1st kind Formula[removed]The following expressions hold for |k

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    Source URL: fractional-calculus.com

    Language: English - Date: 2013-11-11 01:10:58
    4721 Super Calculus of the product of many functions 21.1 Super Integrals of the product of many functions (1) Generalized binomial theorem and Super integral of the product of 2 functions According to the generalized bino

    21 Super Calculus of the product of many functions 21.1 Super Integrals of the product of many functions (1) Generalized binomial theorem and Super integral of the product of 2 functions According to the generalized bino

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    Source URL: fractional-calculus.com

    Language: English - Date: 2013-11-11 05:32:07
    48The normal approximation to the hypergeometric distribution Mark A. Pinsky, Northwestern University 1 Introduction

    The normal approximation to the hypergeometric distribution Mark A. Pinsky, Northwestern University 1 Introduction

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    Source URL: www.dartmouth.edu

    Language: English - Date: 2003-11-11 13:38:55
    493 Generalized Multinomial Theorem 3.1 Binomial Theorem Theorem[removed]If x1, x2

    3 Generalized Multinomial Theorem 3.1 Binomial Theorem Theorem[removed]If x1, x2

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    Source URL: fractional-calculus.com

    Language: English - Date: 2013-11-10 10:09:14
    50UIUC Mock Putnam Exam[removed]Solutions Problem 1. Let a1 = 1, a2 = 1, a3 = −1, and for n > 3 define an by an = an−1 an−3 . Find a2006 . Solution. Computing the first 10 terms of the sequence {an }, we obtain

    UIUC Mock Putnam Exam[removed]Solutions Problem 1. Let a1 = 1, a2 = 1, a3 = −1, and for n > 3 define an by an = an−1 an−3 . Find a2006 . Solution. Computing the first 10 terms of the sequence {an }, we obtain

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    Source URL: www.math.illinois.edu

    Language: English - Date: 2006-10-08 16:27:20